[Idea] a real Earth (if possible)
Posted: Tue Aug 14, 2018 02:05
to check what is needed to accept, to change ...
I mean the Earth as a round ball, in the center of the possible map
- max measures −30912 to 30927 in the axis, mean nearby 61840 nodes place,
and the earth is
- the real radius is 6.371 until 6.378 kilometer, or 12.750 km in diameter
- the highest up hill on land is near 9 km up
- the atmosphere is not so important, rain clouds are 0.5 km and up ... a thunderstorm cloud top from 10 - 15 km
61.000 Nodes place for a ball with 12.750 km full size.
So a factor of up-sizing of 4.5 could be taken, mean 57.375 nodes used, left 3625, is too less for a atmosphere ? ... also difficult to calculate all time
Take a factor of 4:
12.750 km * 4 = 51.000 Nodes used on central axis,
10.000 Nodes left, or in real (/2/4) 1.250 km air space free on the shortest parts from surface to border ... .
seams to much not used space
factor 5 would crash the 8 sizes to the border ... ?
5 * 12.750 = 63.750 is more than the max of: 61840 Nodes (miss 1910, or (/2/5) 191 km at 8 positions)
(if getting these points to the oceans, and let them be smaller ... hmmm)
191 km is already magma area ...
So as using max of space, but keep it more easy to calculate a factor ... (max 61840 Nodes) for 12.750 km
* 4 = 51.000 nodes, rest 10.840 nodes or 1.355 km over smallest area or
* 4.5 = 57.375 nodes, rest 4.465 nodes or 496 km left for air or
* 4.75 = 60.563 nodes, rest 1.277 nodes or 124 km left around ...
* 4.8 = 61.200 nodes, rest 640 nodes or 67 km, hmm
* 4.825 = 61.519 nodes, left 321 nodes what is 33 km space around ...
* 4.85 = 61,838 nodes, left 2 nodes ... just enough to pass flying there ...
So even how to get that basic "ball" with the continental shelf ... a surfave is ok, the inside of earth not needed full, but could let a open triangle to show the inside also ...
I mean the Earth as a round ball, in the center of the possible map
- max measures −30912 to 30927 in the axis, mean nearby 61840 nodes place,
and the earth is
- the real radius is 6.371 until 6.378 kilometer, or 12.750 km in diameter
- the highest up hill on land is near 9 km up
- the atmosphere is not so important, rain clouds are 0.5 km and up ... a thunderstorm cloud top from 10 - 15 km
61.000 Nodes place for a ball with 12.750 km full size.
So a factor of up-sizing of 4.5 could be taken, mean 57.375 nodes used, left 3625, is too less for a atmosphere ? ... also difficult to calculate all time
Take a factor of 4:
12.750 km * 4 = 51.000 Nodes used on central axis,
10.000 Nodes left, or in real (/2/4) 1.250 km air space free on the shortest parts from surface to border ... .
seams to much not used space
factor 5 would crash the 8 sizes to the border ... ?
5 * 12.750 = 63.750 is more than the max of: 61840 Nodes (miss 1910, or (/2/5) 191 km at 8 positions)
(if getting these points to the oceans, and let them be smaller ... hmmm)
191 km is already magma area ...
So as using max of space, but keep it more easy to calculate a factor ... (max 61840 Nodes) for 12.750 km
* 4 = 51.000 nodes, rest 10.840 nodes or 1.355 km over smallest area or
* 4.5 = 57.375 nodes, rest 4.465 nodes or 496 km left for air or
* 4.75 = 60.563 nodes, rest 1.277 nodes or 124 km left around ...
* 4.8 = 61.200 nodes, rest 640 nodes or 67 km, hmm
* 4.825 = 61.519 nodes, left 321 nodes what is 33 km space around ...
* 4.85 = 61,838 nodes, left 2 nodes ... just enough to pass flying there ...
So even how to get that basic "ball" with the continental shelf ... a surfave is ok, the inside of earth not needed full, but could let a open triangle to show the inside also ...